When you reach, (x ± # )(x ± #) , replace x-value in each group with the value opposite of the # so that when added together they should equal zero
The x-value in each grouping is the zero
Real Life Application
You can use quadratic equations in different jobs, such as finding appropriate dimensions for things like paintings, landmarks, etc.
Practice:
Factor 3x^2 - 17x + 10
Section 3: Solving Quadratic Equations by Finding Square Roots
Vocabulary
Square Root: a number r is a square root of a number s; r² = s , √s = r
Radical Sign: √
Radicand: the number or expression beneath the radical sign
Radical: the expression √s where s is a number
Rationalizing the Denominator: process of eliminating a radical in the denominator of a fraction by multipling both the denominator and the numerator by denominator
Properties of Square Roots
Product Property:√ab = (√a)(√b)
Quotient Property: √a/b = √a/b
Solving Quadratic Equations using Square Roots
Write original equation
Get to the point where only the x²-values are on one side and only a number is on the other side
Take the square root of both sides
Simplify
Remember the answer will be both ±
Finding a Falling Object's Height using Quadratic Function
h = -16t²+ h₀
h is the feet; t is the seconds after the objects dropped; h₀ is the initial height
Real Life Application
You can model real life quantities, such as the height of a rock dropped off the Leaning Tower of Pisa
Practice:
Slove 2x^2 + 1 = 17
Section 4: Complex Numbers
Vocabulary
Imaginary Unit: defined as i. i= √-1 , i² = -1
Complex Number: a + bi where a and b are real numbers and i is the imaginary unit; a is always the real part of the complex number and bi is the imaginary part
Imaginary Number: complex number a + bi where b ≄ 0
Complex Plane: Coordinate plane where each point is (a,b) represents a + bi. Horizontal axis is for real numbers and vertical axis is for imaginary numbers.
Complex Conjugates: Two complex numbers, a + bi and a - bi. The product is always a real number
Square Root of Negative Numbers
If r is a positive real number, then √-r = i√r
If r is a postive real number and follows the above, then (i√r)² = -r
Solving a Quadratic Equation
Write original equation
Get to the point where only the x²-values are on one side and only a number is on the other side
Take the square root of each side
Write in terms of i when taking the square root of a negative number
Simplify the radical
Remember the answer will be both ±
Plotting Complex Numbers
The normal x-axis is now the Real Number axis, like wise the normal y-axis is now the Imaginary Number axis
Starting at the origin; the a value of the equation will follow the Real Number axis, the b value of the equation will follow the Imaginary Number Axis.
Multiplying Complex Numbers
Use the Distributive Property or FOIL
Get all the number and values on to one side
Simplify and use i² = -1
Answer should be in standard form; a± bi
Dividing Complex Numbers
Multiply the denominator and the numerator by the conjugate
Use FOIL
Simplify
Answer should be in standard form; a± bi
Absolute Values of Complex Numbers
|z| = √a² +√b²
Used to find the number's distance from the origin in the complex plane
When solving the i-value is disregarded
Real Life Application
You can use complex numbers to solve problems, such as determining whether a complex number belongs to the Mandelbrot set Practice:
Slove 3x^2 + 10 = -26
Section 5- Completing The Square
Completing The Square: process that allows you to write an expression of the form x² + bx as the square binomial c = (b/2)²
Solving quadratic equation when coefficient of x² is 1:
1) set equation to x² + bx = c
2) add (b/2)² to both sides
3) factor into (x + b/2)²
4) square root both sides.
5) solve for x
Solving quadratics when coefficient of x² is not 1:
1) divide each side by coefficient of x²
2) set equation to x² + bx = c
3) add (b/2)² to both sides
4) factor into (x + b/2)²
5) square root both sides
6) solve for x
Real Life Application-
This is good for firefighters, because it can help them figure out where to position a fire hose where it would be most effective against the fire
Practice:
Slove x^2 + 10x - 3 = 0 by completing the square
Real Life Application-
This is good if you own an amusement park, because you can find the speed and duration of thrill rides by using the quadratic formula and the discriminant
Practice:
Solve 2x + x = 5
Section 7- Graphing and Solving Quadratic Inequalities
Quadratic inequalities with 2 variables: y>ax² + bx + c ; y>ax² + bx + c ; y<ax² + bx + c ; y<ax² + bx + c Quadratic inequalities with 1 variable: ax² + bx + c<0 ; ax² + bx + c<0 ; ax² + bx + c> 0 ; ax² + bx + c> 0
1) Graph as you would a regular equation, remembering to use dashed or solid lines
2) pick a point and plug it in the equation to see if it's true or false.
3) shade on the appropriate side
Shade the region that makes the equation true.
When shading:
If shading the outside- OR statement (ex. x< -2 or x> 1)
If shading inside- AND statement (ex. -2 < x <1)
Real Life Application-
You can solve real life problems like finding the weight of theater equipment that certain kinds of rope can support without breaking
Practice:
Graph y > x^2 - 2x - 3
Label Vertex, Axis and two other points.
Section 8- Modeling with Quadratic Functions Quadratic: function that represents a real data set Vertex Form: y = a(x-h)² + k Intercept Form: y = a(x-p)(x-q)
Taking the vertex & given point and putting it into an equation:
1) Take the vertex points and put it in the equation so it's y = a(x-h)² + k
2) Substitute the given point for x and y
3) Solve for the value of a.
4) Write the equation
Using intercepts to write an equation:
1) Put the intercepts into the equation
2) Substitute the given point for x and y
3) solve for a
4) write equation
Real Life Application-
You can solve important problems like determining the effect of wind on a runner's performance Practice:
Answers:
Vertex: (2,-2) Axis: x=2
(3x – 2)(x – 5)
2 square roots of 2 and -2 square roots of 2
X = + or 2i square roots of 3
X = -5 + or – 2 square roots of 7
X = about 1.35 and x = about -1.85
Vertex: (1,4) Axis: x = 1 Other Points: (-1,0) and (3,0)
Section 1: Graphing Quadratic Equations
Vocabulary
Quadratic Function: y = ax² + bx + c- Parabola: graph of a quadratic function; U-shaped
- Vertex: lowest or highest point on the parabola
- Axis of Symmetry: Vertical line that passes through the vertex;
x = - b / 2aForms of Graphing & How to Graph them
- Standard Form
- Vertex Form
- Intercept Form
To turn Vertex or Intercept Form into Standard Form
Real Life Application
You can model real-life archeing objects with Parabolas, such as the golden gate bridge.
Practice:
Graph y = 2x^2 – 8x + 6
Label Vertex axis of symmetry and two other points.
Section 2: Solving Quadratic Equations by Factoring
Vocabulary
Factoring Trinomials
To factor x² + bx + c
- Find integers m and n
- x² + bx + c = (x + m)(x + n) = (x² + mx) + (nx + mn)
- The sum of m and n must equal b, and the product of m and n must equal c
To factor ax ² + bx + cFactoring Patterns
Zero Product Property
Finding Zeros
Real Life Application
You can use quadratic equations in different jobs, such as finding appropriate dimensions for things like paintings, landmarks, etc.
Practice:
Factor 3x^2 - 17x + 10
Section 3: Solving Quadratic Equations by Finding Square Roots
Vocabulary
Properties of Square Roots
Solving Quadratic Equations using Square Roots
Finding a Falling Object's Height using Quadratic Function
Real Life Application
You can model real life quantities, such as the height of a rock dropped off the Leaning Tower of Pisa
Practice:
Slove 2x^2 + 1 = 17
Section 4: Complex Numbers
Vocabulary
Square Root of Negative Numbers
Solving a Quadratic Equation
Plotting Complex Numbers
Multiplying Complex Numbers
Dividing Complex Numbers
Absolute Values of Complex Numbers
Real Life Application
You can use complex numbers to solve problems, such as determining whether a complex number belongs to the Mandelbrot set
Practice:
Slove 3x^2 + 10 = -26
Section 5- Completing The Square
Completing The Square: process that allows you to write an expression of the form x² + bx as the square binomial
c = (b/2)²
Solving quadratic equation when coefficient of x² is 1:
1) set equation to x² + bx = c
2) add (b/2)² to both sides
3) factor into (x + b/2)²
4) square root both sides.
5) solve for x
Solving quadratics when coefficient of x² is not 1:
1) divide each side by coefficient of x²
2) set equation to x² + bx = c
3) add (b/2)² to both sides
4) factor into (x + b/2)²
5) square root both sides
6) solve for x
Real Life Application-
This is good for firefighters, because it can help them figure out where to position a fire hose where it would be most effective against the fire
Practice:
Slove x^2 + 10x - 3 = 0 by completing the square
Section 6- Quadratic Formula and Discriminant
Quadratic Formula- x = -b ± √b² - 4ac / 2a
Discriminant- b² - 4ac
If:
b² - 4ac > 0 ; 2 real solutions
b² - 4ac < 0 ; 2 imaginary solutions
b² - 4ac = 0 ; 1 real solution
Real Life Application-
This is good if you own an amusement park, because you can find the speed and duration of thrill rides by using the quadratic formula and the discriminant
Practice:
Solve 2x + x = 5
Section 7- Graphing and Solving Quadratic Inequalities
Quadratic inequalities with 2 variables: y>ax² + bx + c ; y>ax² + bx + c ; y<ax² + bx + c ; y<ax² + bx + c
Quadratic inequalities with 1 variable: ax² + bx + c<0 ; ax² + bx + c<0 ; ax² + bx + c> 0 ; ax² + bx + c> 0
1) Graph as you would a regular equation, remembering to use dashed or solid lines
2) pick a point and plug it in the equation to see if it's true or false.
3) shade on the appropriate side
Shade the region that makes the equation true.
When shading:
If shading the outside- OR statement (ex. x< -2 or x> 1)
If shading inside- AND statement (ex. -2 < x <1)
Real Life Application-
You can solve real life problems like finding the weight of theater equipment that certain kinds of rope can support without breaking
Practice:
Graph y > x^2 - 2x - 3
Label Vertex, Axis and two other points.
Section 8- Modeling with Quadratic Functions
Quadratic: function that represents a real data set
Vertex Form: y = a(x-h)² + k
Intercept Form: y = a(x-p)(x-q)
Taking the vertex & given point and putting it into an equation:
1) Take the vertex points and put it in the equation so it's y = a(x-h)² + k
2) Substitute the given point for x and y
3) Solve for the value of a.
4) Write the equation
Using intercepts to write an equation:
1) Put the intercepts into the equation
2) Substitute the given point for x and y
3) solve for a
4) write equation
Real Life Application-
You can solve important problems like determining the effect of wind on a runner's performance
Practice:
Answers:
Vertex: (2,-2) Axis: x=2
(3x – 2)(x – 5)
2 square roots of 2 and -2 square roots of 2
X = + or 2i square roots of 3
X = -5 + or – 2 square roots of 7
X = about 1.35 and x = about -1.85
Vertex: (1,4) Axis: x = 1 Other Points: (-1,0) and (3,0)